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2x^2=1286408
We move all terms to the left:
2x^2-(1286408)=0
a = 2; b = 0; c = -1286408;
Δ = b2-4ac
Δ = 02-4·2·(-1286408)
Δ = 10291264
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{10291264}=3208$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-3208}{2*2}=\frac{-3208}{4} =-802 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+3208}{2*2}=\frac{3208}{4} =802 $
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